Let's pick a point n the shaded region of the top left graph ⇒ (0, - 5) = (x, y)
Put this into the inequalities
(-5)+ 3(0) ≥ 2 not true....so....we can stop here
Pick a point in the shaded region in the top right graph ⇒ (1, 0) ⇒ (x, y)
(0) + 3(1) ≥ 2
0 +3 ≥ 2 true
0 + 4 ≥ (1/2) (1)
0 + 4 ≥ 1/2 true
Since this point makes both inequalities true....this must be the correct graph !!!!