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0
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Guest May 25, 2018
 #1
avatar+92855 
+1

E  is true

 

The function is defined at  x  = 0   as   1

The  limit as  x → 0  exists

F is continuous at  x  = 0    [ the second  part of the piecewise  function "fills in" the "hole' that exists at x = 0  ]

 

 

 

cool cool cool

CPhill  May 25, 2018

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