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You can map △ABC onto △A′B′C′△A′B′C′ by reflecting it over the y-axis and translating it 4 units down, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′△A′B′C′ by reflecting it over line y = x and translating it 5 units right, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′△A′B′C′ by rotating it 90° clockwise about the origin and translating it 5 units right, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′△A′B′C′ by reflecting it over the x-axis and translating it 7 units right, which is a sequence of rigid motions.

Johnnyboy  Dec 11, 2017
 #1
avatar+91213 
+4

You can map △ABC onto △A′B′C′ by reflecting it over the x-axis and translating it 7 units right, which is a sequence of rigid motions.

 

 

 

cool cool cool

CPhill  Dec 11, 2017

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