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avatar+1832 

question number 10 ! 

 

question number 16 

 

 

question number 19 

and this question ! 

 Aug 10, 2014

Best Answer 

 #2
avatar+4473 
+13

Question 10: Note that since the lines are parallel, their slopes must be the same [and negative since the line is going downward] and they also differ in their y-intercepts [one + and one -] as well based on the graph. 

D does have the same slope, but notice that both y-intercepts are positive...the graph has 1 equation that has a negative y-intercept.

C also has one that is x -y which means the x would become positive again once it is moved to the other side...while the other equation still has a negative x...

A has x, 2x, and 2y, so notice that the slopes would dramatically differ...

Only B makes sense since you notice that x + y = # andx + y = -#...the slopes are equal and the #'s are opposite signs.

 

 

Question 16: y is definitely greater than 0...but notice that is restricted to a maximum of y = 3. Only choice C makes sense.

 

Question 19: On the graph, when x = 1 when y = 0.

y = -ln x --> 0 = - ln(1)...Yes!

y = e^-x --> 0 = e^(-1)...No!

y = e^x --> 0 = e^1...No!

y = ln x --> 0 = ln 1...Yes!

Now, notice that if we took ln(0.9) we would get -0.1053605156578263...and this graph is in the positive range when x <1...so, -lnx would make it positive...A.

 Aug 10, 2014
 #1
avatar+115747 
+13

I'm going to do the last one  

 

$$y=\sqrt{25-x^2}\\
when\; x=4\\
y=\sqrt{25-16}=\sqrt9=3$$

So you have a rectangle with length 2 units and height 3 units.

So the area is 2*3=6u^2

 Aug 10, 2014
 #2
avatar+4473 
+13
Best Answer

Question 10: Note that since the lines are parallel, their slopes must be the same [and negative since the line is going downward] and they also differ in their y-intercepts [one + and one -] as well based on the graph. 

D does have the same slope, but notice that both y-intercepts are positive...the graph has 1 equation that has a negative y-intercept.

C also has one that is x -y which means the x would become positive again once it is moved to the other side...while the other equation still has a negative x...

A has x, 2x, and 2y, so notice that the slopes would dramatically differ...

Only B makes sense since you notice that x + y = # andx + y = -#...the slopes are equal and the #'s are opposite signs.

 

 

Question 16: y is definitely greater than 0...but notice that is restricted to a maximum of y = 3. Only choice C makes sense.

 

Question 19: On the graph, when x = 1 when y = 0.

y = -ln x --> 0 = - ln(1)...Yes!

y = e^-x --> 0 = e^(-1)...No!

y = e^x --> 0 = e^1...No!

y = ln x --> 0 = ln 1...Yes!

Now, notice that if we took ln(0.9) we would get -0.1053605156578263...and this graph is in the positive range when x <1...so, -lnx would make it positive...A.

AzizHusain Aug 10, 2014
 #3
avatar+1832 
+8

verrrry niiiice ... 

 

I understand all question 

 

thank you melody and aziz

 Aug 10, 2014

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