why doesn't sqrt(8^2+3^2) = 11 ?
Remember the order of operation? First, you have to evaluate the terms INSIDE the brackets.
(8^2 + 3^2)=64 + 9=73. Now, you can see why? Because sqrt(73)=~8.54. IF you had them as separate terms: sqrt(8^2) + sqrt(3^2)=8 + 3 =11. I suppose this is what confused you.
But that's just the notation that the text uses, actual equation is
\(\sqrt{}8^2+3^2\)
No brackets, do BODMAS operators which is the squares n the roots first
why not 11?
the squares n the roots cancel each other out
You STILL have to sum them up first while under sqrt sign!!. Remember this √ sign is like brackets. When you are adding two terms, you still have to evaluate them first. Sqrt[ 8^2 + 3^2] is NOT the same as sqrt(8^2) + sqrt(3^2). Suppose you had: sqrt(8 + 3)=sqrt(11)=3.31..... AND sqrt(8) + sqrt(3)=4.56.......As you can see, they are two different things.
