How does this
Lim h-->0 (bh-1 / h) = 1
Translate to this
Lim h-->0 (bh) = Lim h-->0 (1+h)
My book stated this. I am confused to how they did it. Help.
Use L'hopital's rule:
limh→0(bh-1)/h → limh→0(bhlog(b)/1) → b0log(b) → log(b)