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How does this

Lim h-->0   (bh-1 / h) = 1

Translate to this

Lim h-->0 (bh) = Lim h-->0 (1+h)

 

My book stated this. I am confused to how they did it. Help.

 

Thanks.

 Aug 2, 2017
 #1
avatar+27578 
+1

Use L'hopital's rule:

 

limh→0(bh-1)/h → limh→0(bhlog(b)/1) → b0log(b) → log(b)

 Aug 2, 2017

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