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Why is y=(sin(2x))/(2sinx) only undefined at the y-intercept, and not for all pi values after?

 Nov 12, 2016
 #1
avatar+33653 
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sin2x can be written as 2sinx*cosx, so sin2x/(2sinx) → cosx 

 

(this is, in fact, defined at x = 0)

.

 Nov 12, 2016
 #2
avatar+129840 
0

It isn't defined at any multiple of  pi
 

sin(2x) / [2sin(x)], for x =  0   →   undefined

 

sin(2x) / [2sin(x)], for x =  pi   →   undefined      .....etc....

 

You can check this here, by evaluating x for any pi multiple : 

https://www.wolframalpha.com/input/?i=sin(2x)+%2F+%5B2sin(x)%5D,+for+x%C2%A0%3D+0

 

 

 

cool cool cool

 Nov 12, 2016

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