Jenny has six blouses, four different skirts, 20 different pairs of socks, and four pairs of shoes in her closet at the end of the week.

why would methods used in the previous two problems be inefficient in determining the number of different outfits Jenny could wear?

previously:

1. In his closet, John has one red shirt, one blue shirt, one pair of shorts, one pair of jeans, and a pair of slacks.

2. John discovered that he also has a pair of boots and a pair of dress shoes in his closet.

Guest Nov 28, 2018

#1**+2 **

The previous examples had very few choices and hence a low number of possible combinations. THIS example has

6 x 4 x 20 x4 combinations =1920 combinations..... THAT is a very large tree to draw!

ElectricPavlov Nov 28, 2018