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With 5 resistors of 40 Ohms each, how do you combine to get:

a.48 Ohms

b.32 Ohms

c.50 Ohms

d.80 Ohms

Series                            Parallel

Rt = R1 +R2.......           1/Rt = 1/R1 + 1/R2.....

 Oct 5, 2015

Best Answer 

 #1
avatar+26400 
+30

With 5 resistors of 40 Ohms each, how do you combine to get:

a.48 Ohms

b.32 Ohms

c.50 Ohms

d.80 Ohms

Series                            Parallel

Rt = R1 +R2.......           1/Rt = 1/R1 + 1/R2.....

 

a. 48 Ohms \(\begin{array}{rcccl} &+&- R_1 - R_2 - R_3-&+& \\ -&|& &|&-\\ &+&-- R_4 - R_5-- &+& \end{array}\)

 

b. 32 Ohms \(\begin{array}{rcccl} &+&- R_1 - R_2 - R_3- R_4-&+& \\ -&|& &|&-\\ &+&----- R_5 ----- &+& \end{array}\)

 

 

c. 50 Ohms \(\begin{array}{rcccl} &+& - R_1 - &+& \\ &+& - R_2 - &+& \\ -&|& &|&-- R_5 --\\ &+& - R_3 - &+& \\ &+& - R_4 - &+& \end{array}\)

 

 

d. 80 Ohms \(\begin{array}{rcccl} &+& - R_1 - R_2 - &+& \\ -&|& &|&-- R_5 --\\ &+& - R_3 - R_4 - &+& \end{array}\)

 

laugh

 Oct 6, 2015
 #1
avatar+26400 
+30
Best Answer

With 5 resistors of 40 Ohms each, how do you combine to get:

a.48 Ohms

b.32 Ohms

c.50 Ohms

d.80 Ohms

Series                            Parallel

Rt = R1 +R2.......           1/Rt = 1/R1 + 1/R2.....

 

a. 48 Ohms \(\begin{array}{rcccl} &+&- R_1 - R_2 - R_3-&+& \\ -&|& &|&-\\ &+&-- R_4 - R_5-- &+& \end{array}\)

 

b. 32 Ohms \(\begin{array}{rcccl} &+&- R_1 - R_2 - R_3- R_4-&+& \\ -&|& &|&-\\ &+&----- R_5 ----- &+& \end{array}\)

 

 

c. 50 Ohms \(\begin{array}{rcccl} &+& - R_1 - &+& \\ &+& - R_2 - &+& \\ -&|& &|&-- R_5 --\\ &+& - R_3 - &+& \\ &+& - R_4 - &+& \end{array}\)

 

 

d. 80 Ohms \(\begin{array}{rcccl} &+& - R_1 - R_2 - &+& \\ -&|& &|&-- R_5 --\\ &+& - R_3 - R_4 - &+& \end{array}\)

 

laugh

heureka Oct 6, 2015

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