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with the equation of (3xn)+(n-1) find the slope-intercept form and point-slope form (using the point when n = 3). Graph the equation, and mark the points that correspond to n = 2 and n = 4.

 Mar 18, 2021
 #1
avatar+118015 
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y =  (3n) + ( n - 1) =  2n - 1

 

When  n  =  3.....then  y = 2(3)   -1   = 5

 

When n = 2  then  y  =  2(2) - 1   = 3

 

When n = 4 , then y = 2(4)  - 1

 

Using x  for n...the slope = 2

 

Using  ( 3 , 5)

 

Point-slope   is  (y - 5)  = 2(x - 3)

 

Slope - int   is    y = 2(x - 3) + 5  ⇒  y  = 2x - 6 + 5  ⇒ y=  2x  - 1 

 

 

 

Here's the graph and the points  : https://www.desmos.com/calculator/bgp0oajbn5

 

 

 

 

 

cool cool cool

 Mar 18, 2021
 #2
avatar+363 
0

The equation form 1.2 of week 6 is 3xn+n-1

The point-slope is (Y-1)=3(x-1)

The slope-intercept is Y=3x-2

 Mar 18, 2021

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