With the right triangle ABC, angle B=28 degrees, and side c=54.8in. what is side A
It depends upon whether side 'c" is a leg or the hypoteneuse
If its the hypoteneuse, then angle A = 90 - 28 = 62
And we have
sin(62) = A / 54.8 multiply both sides by 54.8
54.8 sin (62) = A = about 48.39 in.
If c is a leg, then A has to be the hypoteneuse (or else angle B would = 90)
So....angle C = 62 degrees and we have
sin (62) = 54.8 / A rearranging, we have
A = 54.8 / sin(62) = about 62.06 in.
It depends upon whether side 'c" is a leg or the hypoteneuse
If its the hypoteneuse, then angle A = 90 - 28 = 62
And we have
sin(62) = A / 54.8 multiply both sides by 54.8
54.8 sin (62) = A = about 48.39 in.
If c is a leg, then A has to be the hypoteneuse (or else angle B would = 90)
So....angle C = 62 degrees and we have
sin (62) = 54.8 / A rearranging, we have
A = 54.8 / sin(62) = about 62.06 in.