A girl places a stick at an angle of 60.0° against a flat rock on a frozen pond. She pushes at an angle and moves the rock horizontally for 2.00 m across the pond at a velocity of 4.00 m/s and a power of 160.0 W. What force did she apply to the stick? How much work did she do?

Guest Feb 11, 2020

#1**+2 **

Power = Force * velocity

force parallel to movement would be F cos 60

Power = F cos 60 * 4 m/s

160 W = F cos 60 * 4 m/s

160 kg-m^{2}/s^{3 }= ( F cos 60) kg-m/s^{2 } * 4 m/s Solve for F (which will be in Newtons A newton is kg-m/s^{2)}

Then use the "F" found above:

Work = F * d = F * 2 m

ElectricPavlov Feb 11, 2020

#1**+2 **

Best Answer

Power = Force * velocity

force parallel to movement would be F cos 60

Power = F cos 60 * 4 m/s

160 W = F cos 60 * 4 m/s

160 kg-m^{2}/s^{3 }= ( F cos 60) kg-m/s^{2 } * 4 m/s Solve for F (which will be in Newtons A newton is kg-m/s^{2)}

Then use the "F" found above:

Work = F * d = F * 2 m

ElectricPavlov Feb 11, 2020