A girl places a stick at an angle of 60.0° against a flat rock on a frozen pond. She pushes at an angle and moves the rock horizontally for 2.00 m across the pond at a velocity of 4.00 m/s and a power of 160.0 W. What force did she apply to the stick? How much work did she do?
+36915 Power = Force * velocity
force parallel to movement would be F cos 60
Power = F cos 60 * 4 m/s
160 W = F cos 60 * 4 m/s
160 kg-m2/s3 = ( F cos 60) kg-m/s2 * 4 m/s Solve for F (which will be in Newtons A newton is kg-m/s2)
Then use the "F" found above:
Work = F * d = F * 2 m
+36915 Power = Force * velocity
force parallel to movement would be F cos 60
Power = F cos 60 * 4 m/s
160 W = F cos 60 * 4 m/s
160 kg-m2/s3 = ( F cos 60) kg-m/s2 * 4 m/s Solve for F (which will be in Newtons A newton is kg-m/s2)
Then use the "F" found above:
Work = F * d = F * 2 m
