Work out the value of n.
1/32÷^3√2=2^n
Give your answer as an improper fraction.
Work out the value of n.
1/32÷^3√2=2^n
Give your answer as an improper fraction.
Mmmm do you mean
1/32÷(cube root of 2)=2^n
\(\frac{1}{32}\div \sqrt[3]{2}=2^n\\ \frac{1}{2^5}\div 2^{1/3}=2^n\\ 2^{-5}\div 2^{1/3}=2^n\\ 2^{(-5-\frac{1}{3})}=2^n\\ 2^{(-5\frac{1}{3})}=2^n\\ n=-5\frac{1}{3}\)
\(n=\frac{-16}{3}\)