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Five workers have been hired to complete a job.  If one additional worker is hired, they could complete the job $8$ days earlier.  If the job needs to completed $28$ days earlier, how many additional workers should be hired?

 Aug 25, 2023
 #1
avatar+129895 
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Number of workers * number of days  = total job done = number of work units

 

So....let N be the original number of  days  and N - 8  = 8 days earlier and we  have this equation

 

5 N = 6 ( N - 8)

 

5N = 6N  - 48

 

48 = 6N - 5N

 

48 = N

 

And the amt of  work  that the  job requires =  5 * 48 =  240 work units

 

So...if the  job could be be completed 28 days earlier we have this equation where W is the  number of  workers  needed

 

W  ( 48 - 28) =  240

 

W ( 20)   = 240

 

W = 240 / 20    =   12 

 

So....  12 - 5 =  7 additional workers  should be hired to complete the   job 28 days  earlier

 

cool cool cool

 Aug 25, 2023
edited by CPhill  Aug 25, 2023

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