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Write a equation of each circle.

Center at ( -3, -3), passes through ( -2,3)

 Feb 4, 2016
 #1
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We   need to find the radius......this is given by

 

sqrt [ (-2 - - 3)^2  + ( -3 - 3)^2  ]   =  sqrt [ 1^2 + (-6)^2]  =  sqrt(37)

 

So.........the equation is :

 

(x - x coordinate of the center)^2 + (y - y coordinate of the center)^2  =  radius^2

 

(x - - 3)^2  + ( y - - 3)^2   = 37

 

(x + 3)^2  + ( y + 3)^2   = 37

 

 

cool cool cool

 Feb 4, 2016

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