"Write a funcion y= ¼(x-6)^2 in y=ax^2+bx+c" The answer is ¼x^2-3x-9. I just want to know how do you solve this formula.
Starting with: y = ¼(x - 6)2
First: expand: (x - 6)2 ---> (x - 6)2 = (x - 6)(x - 6) = x2 - 12x + 36
Then: multiply this answer by ¼ ---> ¼(x2 - 12x + 36) = ¼(x2) + ¼(-12x) + ¼(36) = ¼x2 - 3x + 9
