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Center:(7,-3) ,passes thru the origin

 Nov 28, 2018

Best Answer 

 #1
avatar+19701 
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Center at 7,-3  and passes thru the origin...

  Radius is distance from center to origin

     sqrt(7^2 +3^2) = SQRT 58 = r

 

circle with center at h,k      (x-h)^2 +(y-k)^2 = r^2

so the circle in question is given by        (x-7)^2 + (y+3)^2 = 58

 Nov 28, 2018
 #1
avatar+19701 
0
Best Answer

Center at 7,-3  and passes thru the origin...

  Radius is distance from center to origin

     sqrt(7^2 +3^2) = SQRT 58 = r

 

circle with center at h,k      (x-h)^2 +(y-k)^2 = r^2

so the circle in question is given by        (x-7)^2 + (y+3)^2 = 58

ElectricPavlov Nov 28, 2018

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