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write the equation of a hyperbola with vertices at (4,0) and (-4,0) and covertices at (0,5) and (0,-5)

Guest Jul 4, 2014

Best Answer 

 #1
avatar+81063 
+10

x^2/16 - y^2/25  = 1

 

 

CPhill  Jul 5, 2014
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4+0 Answers

 #1
avatar+81063 
+10
Best Answer

x^2/16 - y^2/25  = 1

 

 

CPhill  Jul 5, 2014
 #2
avatar+91479 
0

I don't understand this Chris, could you please explain it to me.

What is a covertice?

I did the graph.

Melody  Jul 5, 2014
 #3
avatar+26406 
+5

I've not come across the term "covertices" before either Melody.  However, it is clear that they are the vertices of the hyperbola obtained by interchanging the signs of the x and y terms.  See graph below:

hyperbolae

Alan  Jul 5, 2014
 #4
avatar+91479 
0

Thank you Alan and Chris,

I would not have had a clue about any of this question.

I am completely unfamiliar with graphs like these which actually surprises me.

I am only familiar with the diagonal hyperbolas with no squared terms.  

Melody  Jul 5, 2014

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