+196 Write the standard equation of the parabola with its vertex at (3,2) and its focus at (3,0)
A) -8(y-2)=(x-3)^2
B) 8(y-2)=(x-3)^2
C)12(x-3)=(y-2)^2
D) -12(x-3)=(y-2)^2
+130071 The form is given by:
(x - h)2 = 4p (y - k)
The vertex is given by (h,k) = (3,2)
And.....we have a parabola with its focus that will lie 2 units below the vertex.......so p = -2
So we have
(x - 3)2 = 4(-2)(y - 2)
(x - 3)2 = -8(y - 2) which is the same as
-8(y -2) = (x - 3)2
