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writing sinh inverse (-(48/55)) in logarithim form

 Jul 7, 2014

Best Answer 

 #2
avatar+26400 
+6

writing sinh inverse (-(48/55)) in logarithim form

$$\\\boxed{\sinh^{-1}{(x)}=\ln{(x+ \sqrt{x^2+1} }) }\\ \\
\sinh^{-1}{( -{48 \over 55} )}
= \ln{ \left(-{48 \over 55}
+\sqrt{ (-{48 \over 55} )^2+1}
\right)} \\\\
=\ln{(0.45454545455)}\\\\
=-0.78845736036$$

 Jul 7, 2014
 #1
avatar+33665 
+5

inverseSinh

Alan Jul 7, 2014
 #2
avatar+26400 
+6
Best Answer

writing sinh inverse (-(48/55)) in logarithim form

$$\\\boxed{\sinh^{-1}{(x)}=\ln{(x+ \sqrt{x^2+1} }) }\\ \\
\sinh^{-1}{( -{48 \over 55} )}
= \ln{ \left(-{48 \over 55}
+\sqrt{ (-{48 \over 55} )^2+1}
\right)} \\\\
=\ln{(0.45454545455)}\\\\
=-0.78845736036$$

heureka Jul 7, 2014

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