+0  
 
0
214
1
avatar

how is 2.1^1095 infinity???

Guest Mar 27, 2017
 #1
avatar+92775 
+1

It isn't. It is just too big to be calculated by this, and most other, calculators.

 

Here is your answer if your really want to know.

 

\(y=2.1^{1095}\\ logy=log2.1^{1095}\\ logy=1095log2.1\\\)

 

1095*log(2.1)=  352.8301277336416335

 

\(logy\approx 352.8301277336416335\\ logy\approx 352+0.8301277336416335\\ y\approx 10^{352+0.8301277336416335}\\ y\approx 10^{0.8301277336416335}*10^{352}\\\)

 

10^(0.8301277336416335) = 6.7628185252517102253


\(y\approx 6.7628185252517102253 \times 10^{352}\\ 2.1*10^{1095} \approx 6.7628185252517102253 \times 10^{352}\\\)

Melody  Mar 27, 2017

12 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.