+118667 It isn't. It is just too big to be calculated by this, and most other, calculators.
Here is your answer if your really want to know.
\(y=2.1^{1095}\\ logy=log2.1^{1095}\\ logy=1095log2.1\\\)
1095*log(2.1)= 352.8301277336416335
\(logy\approx 352.8301277336416335\\ logy\approx 352+0.8301277336416335\\ y\approx 10^{352+0.8301277336416335}\\ y\approx 10^{0.8301277336416335}*10^{352}\\\)
10^(0.8301277336416335) = 6.7628185252517102253
\(y\approx 6.7628185252517102253 \times 10^{352}\\ 2.1*10^{1095} \approx 6.7628185252517102253 \times 10^{352}\\\)
