+0  
 
0
680
2
avatar

(x^2 - 1)/lnx+x-1

 Aug 7, 2016
 #1
avatar+15127 
0

 

(x^2 - 1)/lnx+x-1= 0

 

(x² - 1) / lnx + x -1=0

 

x is not defined.

 Aug 7, 2016
 #2
avatar+9676 
+5

\(f(x)=\dfrac{x^2-1}{\ln x}+x-1\\ f(0.0001)=\dfrac{(0.0001)^2-1}{\ln (0.0001)}+0.0001-1\)

= -0.8913263806099232

 Aug 8, 2016

0 Online Users