$${\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{x}}}}\right)}^{{\mathtt{N}}}$$
If the fifth term in this expansion is independant of X, find the value of N
$$(x+\frac{1}{x})^N=x^N+Nx^{N-1}x^{-1}+\frac{N(N-1)}{2!}x^{N-2}x^{-2}+...$$
The fifth term will therefore contain xN-4x-4 or xN-8. For this to be independent of x we must have N - 8 = 0 or N = 8
.