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$${\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{x}}}}\right)}^{{\mathtt{N}}}$$

If the fifth term in this expansion is independant of X, find the value of N

 Jun 28, 2015

Best Answer 

 #1
avatar+33615 
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$$(x+\frac{1}{x})^N=x^N+Nx^{N-1}x^{-1}+\frac{N(N-1)}{2!}x^{N-2}x^{-2}+...$$

 

The fifth term will therefore contain xN-4x-4 or xN-8.  For this to be independent of x we must have N - 8 = 0 or N = 8

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 Jun 29, 2015
 #1
avatar+33615 
+10
Best Answer

$$(x+\frac{1}{x})^N=x^N+Nx^{N-1}x^{-1}+\frac{N(N-1)}{2!}x^{N-2}x^{-2}+...$$

 

The fifth term will therefore contain xN-4x-4 or xN-8.  For this to be independent of x we must have N - 8 = 0 or N = 8

.

Alan Jun 29, 2015

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