[(x + 1) − y]^2

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[(x + 1) − y]^2

Guest Jan 30, 2016

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Best Answer

[(x + 1) − y]^2

This is just a perfect square.

\([(x + 1) − y]^2\\ = (x+1)^2\;\;-\;\;2*(x+1)*y\;\;+\;\;y^2\\ = (x^2+2x+1)\;\;-\;\;2y(x+1)\;\;+\;\;y^2\\ = x^2+2x+1\;\;-\;\;2xy-2y\;\;+\;\;y^2\\\)

Melody Jan 30, 2016

Melody · Answer 1 · 2016-01-30T11:53:26

[(x + 1) − y]^2

This is just a perfect square.

\([(x + 1) − y]^2\\ = (x+1)^2\;\;-\;\;2*(x+1)*y\;\;+\;\;y^2\\ = (x^2+2x+1)\;\;-\;\;2y(x+1)\;\;+\;\;y^2\\ = x^2+2x+1\;\;-\;\;2xy-2y\;\;+\;\;y^2\\\)