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x 10exp(−0.17x)=1 what is the value of x

 Nov 17, 2015

Best Answer 

 #6
avatar+118724 
+5

Ok so mine is correct for the question that I answered.

 

A question to the asker.

Why would you write exp if you meant 'e' ?

They are not the same thing at all !!

 

Thank you Alan :)

 Nov 17, 2015
 #1
avatar+118724 
+5

Mmmm   What is the question?

What is between the x and the 10?

 

x 10exp(−0.17x)=1 what is the value of x

 

x ? 10^(-0.17x) = 1

Is it meant to be multiply??

 

\(x \times 10^{-0.17x} = 1\\ x \times \frac{10^{-0.17x}}{1} = 1\\ x \times \frac{1} {10^{0.17x}}= 1\\ x=10^{0.17x} \\ log x=0.17x\)

 

I am going to cheat a bit and get a graphical solution

I am graphing y=log(x)  and  y=0.17x

Looks to me like there is no solution since the 2 graphs don't intersect.

 

Can someone check this please?

 Nov 17, 2015
 #2
avatar+33665 
+5

Here are graphs showing two solutions and the corresponding numerical values obtained using Newton-Raphson:

 

numerical solutions

 Nov 17, 2015
 #3
avatar+118724 
0

Alan, could you please what is wrong with my logic ?

 Nov 17, 2015
 #4
avatar+33665 
+5

Need 10exp(-0.17x) to be interpreted as 10*e^(-0.17x) rather than 10^(-0.17x).

 Nov 17, 2015
 #6
avatar+118724 
+5
Best Answer

Ok so mine is correct for the question that I answered.

 

A question to the asker.

Why would you write exp if you meant 'e' ?

They are not the same thing at all !!

 

Thank you Alan :)

Melody Nov 17, 2015

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