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X^2-12X+27=0

 Oct 4, 2014

Best Answer 

 #1
avatar+3453 
+5

X^2-12X+27=0        

The right side can be factored out. Think, what times what equals 27, and have those two numbers add up to -12, well it turns out that -9 and -3 work, because -3 x -9 = 27, and -3 + -8 = 12.

(x-9)(x-3)=0        

Now use the "zero product property" which says that if you have two numbers multiplied together equal zero, then one of these numbers has to be zero. This means we can set each factor to 0, and solve.

(x-9)(x-3)=0         ---Set each factor to zero

(x-9) = 0 | (x-3)=0  

  +9   +9      +3  +3

----------------------------

x = 9 | x = 3

 

The two solutions are x = 9 and x = 3.

 Oct 4, 2014
 #1
avatar+3453 
+5
Best Answer

X^2-12X+27=0        

The right side can be factored out. Think, what times what equals 27, and have those two numbers add up to -12, well it turns out that -9 and -3 work, because -3 x -9 = 27, and -3 + -8 = 12.

(x-9)(x-3)=0        

Now use the "zero product property" which says that if you have two numbers multiplied together equal zero, then one of these numbers has to be zero. This means we can set each factor to 0, and solve.

(x-9)(x-3)=0         ---Set each factor to zero

(x-9) = 0 | (x-3)=0  

  +9   +9      +3  +3

----------------------------

x = 9 | x = 3

 

The two solutions are x = 9 and x = 3.

NinjaDevo Oct 4, 2014

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