(-x^2/2)^2

Question

0

580

1

(-x^2/2)^2

Guest Jun 19, 2014

+118723

+5

Best Answer

$$\left(\frac{-x^2}{2}\right)^2=\left(\frac{-1\times x^2}{2}\right)^2=
\frac{(-1)^2\times (x^2)^2}{2^2}=
\frac{1\times x^4}{4}= \frac{x^4}{4}$$

Melody Jun 19, 2014

Melody · Answer 1 · 2014-06-19T02:35:34

$$\left(\frac{-x^2}{2}\right)^2=\left(\frac{-1\times x^2}{2}\right)^2=
\frac{(-1)^2\times (x^2)^2}{2^2}=
\frac{1\times x^4}{4}= \frac{x^4}{4}$$

.