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((x^-2)^-2))/((x^-2-y^-2)^-2) = .....
math algebra
 Aug 19, 2014

Best Answer 

 #1
avatar+118723 
+5

$$(x^{-2})^{-2}\div (x^{-2}-y^{-2})^{-2}\\\\
=(x^{-2*-2})\times (x^{-2}-y^{-2})^{+2}\\\\
=(x^{4})\times (\frac{1}{x^2}-\frac{1}{y^2})^{+2}\\\\
=(x^{4})\times (\frac{y^2-x^2}{x^2y^2})^2\\\\
=(x^{4})\times \frac{(y^2-x^2)^2}{x^4y^4}\\\\
=\frac{(y^2-x^2)^2}{y^4}\\\\
=\frac{y^4-2x^2y^2+x^4}{y^2}\\\\

.$$

.
 Aug 19, 2014
 #1
avatar+118723 
+5
Best Answer

$$(x^{-2})^{-2}\div (x^{-2}-y^{-2})^{-2}\\\\
=(x^{-2*-2})\times (x^{-2}-y^{-2})^{+2}\\\\
=(x^{4})\times (\frac{1}{x^2}-\frac{1}{y^2})^{+2}\\\\
=(x^{4})\times (\frac{y^2-x^2}{x^2y^2})^2\\\\
=(x^{4})\times \frac{(y^2-x^2)^2}{x^4y^4}\\\\
=\frac{(y^2-x^2)^2}{y^4}\\\\
=\frac{y^4-2x^2y^2+x^4}{y^2}\\\\

.$$

Melody Aug 19, 2014

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