what is the answer to [(x^2)-20x+(23/3)]'-√576+4!=0?
[(x^2)-20x+(23/3)]'-√576+4!=0
(x2−20x+233)−√576+4!=0(x2−20x+233)−24+24=0x2−20x+233=03x2−60x+23=0x=60±√3600−2766x=60±√33246etc
[(x^2)-20x+(23/3)]'-√576+4!=0?
What is the apostrophy for?
sorry must have put that there by accident...