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(x^2-25)/(x^2+7x+10) What is the first step to solving this?

 Aug 11, 2015

Best Answer 

 #1
avatar+118587 
+5

 

$$\\\frac{(x^2-25)}{(x^2+7x+10)}\\\\
=\frac{(x-5)(x+5)}{(x+5)(x+2)}\\\\
x\ne-2\qquad and \qquad x\ne -5\\\\
=\frac{x-5}{x+2}\\\\$$

.
 Aug 11, 2015
 #1
avatar+118587 
+5
Best Answer

 

$$\\\frac{(x^2-25)}{(x^2+7x+10)}\\\\
=\frac{(x-5)(x+5)}{(x+5)(x+2)}\\\\
x\ne-2\qquad and \qquad x\ne -5\\\\
=\frac{x-5}{x+2}\\\\$$

Melody Aug 11, 2015

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