(x^2-25)/(x^2+7x+10) What is the first step to solving this?

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Guest Aug 11, 2015

+118696

+5

Best Answer

$\\\frac{(x^2-25)}{(x^2+7x+10)}\\\\ =\frac{(x-5)(x+5)}{(x+5)(x+2)}\\\\ x\ne-2\qquad and \qquad x\ne -5\\\\ =\frac{x-5}{x+2}\\\\$

Melody Aug 11, 2015

Melody · Answer 1 · 2015-08-11T05:00:55

$\\\frac{(x^2-25)}{(x^2+7x+10)}\\\\ =\frac{(x-5)(x+5)}{(x+5)(x+2)}\\\\ x\ne-2\qquad and \qquad x\ne -5\\\\ =\frac{x-5}{x+2}\\\\$

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