x^2=27 Please help me find the value for x

x^2=27

\(x^2=27\)

\(x=\pm\sqrt{27}\)

\(x_1=5.19615242271\ \ x_2=-5.19615242271\)

  !

x^2=27

\(x^2=27\\ x=\pm\sqrt{27}\\ x=\pm\sqrt{9*3}\\ x=\pm\sqrt{9}\sqrt{3}\\ x=\pm3\sqrt{3}\\\)