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x^2+2x-1=9

math algebra
 Aug 25, 2014

Best Answer 

 #1
avatar+130511 
+5

x^2+2x-1=9    subtract 9 from both sides

x^2 + 2x - 10 = 0

This won't factor, but we do have two real solutions....we can use the onsite calculator to solve or complete the square. The onsite calculator is easier....!!!

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{10}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{4.316\: \!624\: \!790\: \!355\: \!399\: \!8}}\\
{\mathtt{x}} = {\mathtt{2.316\: \!624\: \!790\: \!355\: \!399\: \!8}}\\
\end{array} \right\}$$

 Aug 25, 2014
 #1
avatar+130511 
+5
Best Answer

x^2+2x-1=9    subtract 9 from both sides

x^2 + 2x - 10 = 0

This won't factor, but we do have two real solutions....we can use the onsite calculator to solve or complete the square. The onsite calculator is easier....!!!

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{10}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{11}}}}{\mathtt{\,-\,}}{\mathtt{1}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{4.316\: \!624\: \!790\: \!355\: \!399\: \!8}}\\
{\mathtt{x}} = {\mathtt{2.316\: \!624\: \!790\: \!355\: \!399\: \!8}}\\
\end{array} \right\}$$

CPhill Aug 25, 2014

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