x^2+3x+25=0 the quadratic formula

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Guest Apr 30, 2015

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Best Answer

$$x=\frac{-3\pm \sqrt{(3^2-4\times1\times25))}}{2\times1}$$

Because the discriminant (the part under the square root sign) is negative, the values of x will be complex numbers.

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Alan May 1, 2015

Alan · Answer 1 · 2015-05-01T07:48:41

$$x=\frac{-3\pm \sqrt{(3^2-4\times1\times25))}}{2\times1}$$

Because the discriminant (the part under the square root sign) is negative, the values of x will be complex numbers.

.