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(x^2-3x-4)(x-3) HELP

 Feb 6, 2017
 #1
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am i finding the solution or expanding it

 Feb 6, 2017
 #2
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idk

 Feb 6, 2017
 #3
avatar+104 
+5

this is the expansion 

Distribute sum groups

{x}^{2}(x-3)-3x(x-3)-4(x-3)x​2​​(x−3)−3x(x−3)−4(x−3)

Distribute

{x}^{3}-3{x}^{2}-3x(x-3)-4(x-3)x​3​​−3x​2​​−3x(x−3)−4(x−3)

Distribute

{x}^{3}-3{x}^{2}-(3{x}^{2}-9x)-4(x-3)x​3​​−3x​2​​−(3x​2​​−9x)−4(x−3)

even more Distribute

{x}^{3}-3{x}^{2}-(3{x}^{2}-9x)-(4x-12)x​3​​−3x​2​​−(3x​2​​−9x)−(4x−12)

Simplify brackets

{x}^{3}-3{x}^{2}-3{x}^{2}+9x-4x+12x​3​​−3x​2​​−3x​2​​+9x−4x+12

Collect like terms

{x}^{3}+(-3{x}^{2}-3x​2​​)+(9x−4x)+12

now you just Simplify

therefor, it is

x^3-6x^2+5x+12

 Feb 6, 2017

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