x+2/4x^2+2x-8

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x+2/4x^2+2x-8

Guest Jan 22, 2015

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Best Answer

$$\\x+\frac{2}{4x^2}+2x-8\\\\
=\frac{1}{2x^2}+2x+x-8\\\\
=\frac{1}{2x^2}+3x-8\\\\$$

Melody Jan 23, 2015

Melody · Answer 1 · 2015-01-23T01:01:16

$$\\x+\frac{2}{4x^2}+2x-8\\\\
=\frac{1}{2x^2}+2x+x-8\\\\
=\frac{1}{2x^2}+3x-8\\\\$$

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