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x^2-4x+3=4x-13

 Dec 27, 2014

Best Answer 

 #1
avatar+23246 
+5

x² - 4x + 3  =  4x - 13

Subtract  4x  from both sides:

x² - 8x + 3  =  -13

Add  13  to both sides:

x² - 8x + 16  =  0

Factor:

(x - 4)(x - 4)  =  0

So, either  x - 4  =  0  or  x - 4  =  0

--->               x  =  4    or     x  =  4

Obviously,  x  =  4.

 Dec 27, 2014
 #1
avatar+23246 
+5
Best Answer

x² - 4x + 3  =  4x - 13

Subtract  4x  from both sides:

x² - 8x + 3  =  -13

Add  13  to both sides:

x² - 8x + 16  =  0

Factor:

(x - 4)(x - 4)  =  0

So, either  x - 4  =  0  or  x - 4  =  0

--->               x  =  4    or     x  =  4

Obviously,  x  =  4.

geno3141 Dec 27, 2014

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