( x^2+5)(3+x^4 )( 100x^2−10)( 100x^2+10)=0 when x=?
+130518 ( x^2+5)(3+x^4 )( 100x^2−10)( 100x^2+10)=0
Believe it, or not.....this has only two "real" solutions....and they come from this part of the equation:
100x^2 - 10 = 0 divide through by 10
10x^2 - 1 = 0 add1 to each side
10x^2 - 1 divide both sides by 10
x^2 = 1/10 take the pos/neg roots
x = (pos/neg)[1/sqrt(10)]
