x^2-8x=-16?

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x^2-8x=-16?

Guest Jul 2, 2014

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Best Answer

Let's add 16 to both sides.....this gives

x^2 - 8x + 16 = 0 factoring, we have

(x -4) (x-4) = 0

So, we only need to set one factor to 0....this gives that x = 4

CPhill Jul 2, 2014

CPhill · Answer 1 · 2014-07-02T05:17:23

Let's add 16 to both sides.....this gives

x^2 - 8x + 16 = 0 factoring, we have

(x -4) (x-4) = 0

So, we only need to set one factor to 0....this gives that x = 4

Melody · Answer 2 · 2014-07-02T05:17:16

$$\\x^2-8x+16=0\\
(x-4)^2=0\\
x-4=0\\
x=4$$

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