x 2 +8x=48

Solve for x:
x^2+8 x = 48

Add 16 to both sides:
x^2+8 x+16 = 64

Write the left hand side as a square:
(x+4)^2 = 64

Take the square root of both sides:
x+4 = 8 or x+4 = -8

Subtract 4 from both sides:
x = 4 or x+4 = -8

Subtract 4 from both sides:
Answer: |x = 4     or     x = -12

\(x^2+8x-48=0\\ (x+12)(x-4)=0\\ x=-12\\ OR\\ x=4\)

Same ans as Guest #1

thank you so much