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X^2 + ( P x X ) + Q = 0

 Nov 12, 2014

Best Answer 

 #2
avatar+33661 
+5

This might just be:

$$x^2+Px+Q=0$$

in which case:

$$x=\frac{-P\pm \sqrt{P^2-4Q}}{2}$$

.

 Nov 12, 2014
 #1
avatar+118723 
+5

You cannot solve this because there are 2 variables.  You need 2 equations to solve for 2 variables.  

 Nov 12, 2014
 #2
avatar+33661 
+5
Best Answer

This might just be:

$$x^2+Px+Q=0$$

in which case:

$$x=\frac{-P\pm \sqrt{P^2-4Q}}{2}$$

.

Alan Nov 12, 2014

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