(x+2) (x+1) -2 (x+5)
$$\\(x+2)(x+1)-2(x+5)\\ =x(x+1)+2(x+1)-2(x+5)\\ =x^2+x+2x+2-2x-10\\ =x^2+x-8\\$$
$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{8}}$$