(x+2)(x2+3x-5)
(x+2)(x^2+3x-5) distributing the first two terms over the other three, we have
(x)(x^2+3x-5) + (2)(x^2+3x-5) =
x^3 + 3x^2 - 5x + 2x^2 + 6x - 10 =
x^3 + 5x^2 + x - 10