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x^2+y^2+3x-2y-1=0 find the standard form

Guest Oct 29, 2017
 #1
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+2

 

Rewrite as

 

x^2 + 3x + y^2 - 2y = 1

 

Complete the square on x and y

 

x^2 + 3x + 9/4 + y^2 - 2y + 1  =  1  + 9/4  + 1

 

( x + 3/2)^2  +  ( y - 1)^2  =  2 + 9/4

 

( x + 3/2)^2  +  ( y - 1)^2  =  8/4 + 9/4

 

( x + 3/2)^2  +  ( y - 1)^2  =  17/4 

 

 

cool cool cool

CPhill  Oct 29, 2017

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