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x^2+y^2=400

y-12=-1/8(x+16)^2

 Sep 27, 2016
 #1
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[ 2 (sqrt(24-2 y)-8)]^2 + y^2=400, solve for y

 

y=-20 and x=0 or,

y=12 and  x=16

 Sep 27, 2016

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