x^2-y^2=8 x-y=2

x^2-y^2=8
x-y=2            

Using the second thing, we can add y to both sides and subtract 2 from both sides....this gives

y = x - 2      and substituting this into the first equation, we have

x^2 - (x - 2)^2  = 8      expand   and simplify

x^2 - (x^2 - 4x + 4) = 8

x^2 - x^2 + 4x - 4 = 8

4x - 4  = 8      add 4 to both sides

4x = 12         divide by 4

x = 3

And, since y = x - 2. we have   y = 3 - 2 = 1

So....our solution is    (3, 1)

x=3 y=1

3^2=9

1^2=1

9-1=8

3-1=2  

Easiest question that I have seen today

Sorry for the hand writing and long explanation

As I am having H abit to write in pattern suggested by school boards

Yeah, but how get 3 and 1?