Best Answerx−2y=1(1a)x2+y2=13(2)x=1+2yx2=1+4y2+4y(1b)sub1binto21+4y2+4y+y2=135y2+4y−12=05y2+10y−6y−12=05y(y+2)−6(y+2)=0(5y−6)(y+2)=0y=+6/5ory=−2
now sub thes y values back into 1a to find the corresponding x values.
you can finish it :)
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