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(x+3.2)^2+(y+3.5)^2

 May 13, 2014

Best Answer 

 #2
avatar+118677 
+5

That is not correct GoldenLeaf

$$(x + 3.2)^2 + (y + 3.5)^2\\\\
=x^2+(2*3.2x)+3.2^2 + y^2+(2*3.5y)+3.5^2\\\\
=x^2+6.4x+10.24 + y^2+7y+12.25\\\\
=x^2+6.4x+y^2+7y+22.49\\\\$$

 May 13, 2014
 #1
avatar+1006 
0

Well, with no equal sign, it is technically unsolvable. However, it can be simplified into simplest terms.

 

$${\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3.2}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3.5}}\right)}^{{\mathtt{2}}}$$ is what I'm assuming you put here?

 

(x^2 + 10.24) + (y^2 + 12.25)

x^2 + 10.24 + y^2 + 12.25

x^2 + y^2 + 22.49

 

Or, in format, $${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{y}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{24.49}}$$

 May 13, 2014
 #2
avatar+118677 
+5
Best Answer

That is not correct GoldenLeaf

$$(x + 3.2)^2 + (y + 3.5)^2\\\\
=x^2+(2*3.2x)+3.2^2 + y^2+(2*3.5y)+3.5^2\\\\
=x^2+6.4x+10.24 + y^2+7y+12.25\\\\
=x^2+6.4x+y^2+7y+22.49\\\\$$

Melody May 13, 2014

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