x^3+(2x^3+x-3)^3=3
find x
Let s=2x3+x−3, then x3+s3=3, or 3s3⋅x3−3s=0. Factoring out x3, we have x3⋅(3s2−1)=0.
Since s=2x3+x−3=0, we have x3=0, or x=0.
