$${\mathtt{\,-\,}}\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\right){\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}\right) = {\mathtt{14}} \Rightarrow {\mathtt{x}} = {\mathtt{\,-\,}}{\frac{{\mathtt{7}}}{{\mathtt{5}}}} \Rightarrow {\mathtt{x}} = -{\mathtt{1.4}}$$
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