x^3-6x^2-7x+60=0
can you tell me how you got the answer also? I would like to understand this please
Solve for x: x^3-6 x^2-7 x+60 = 0 The left hand side factors into a product with three terms: (x-5) (x-4) (x+3) = 0 Split into three equations: x-5 = 0 or x-4 = 0 or x+3 = 0 Add 5 to both sides: x = 5 or x-4 = 0 or x+3 = 0 Add 4 to both sides: x = 5 or x = 4 or x+3 = 0 Subtract 3 from both sides: Answer: | | x = 5 or x = 4 or x = -3
Solve for x: x^3-6 x^2-7 x+60 = 0 The left hand side factors into a product with three terms: (x-5) (x-4) (x+3) = 0 Split into three equations: x-5 = 0 or x-4 = 0 or x+3 = 0 Add 5 to both sides: x = 5 or x-4 = 0 or x+3 = 0 Add 4 to both sides: x = 5 or x = 4 or x+3 = 0 Subtract 3 from both sides: Answer: | | x = 5 or x = 4 or x = -3
